**A photon of wavelength 6000 Å has an energy E. The wavelength of the photon of light which corresponds to an energy equal to 2E is**

**Option 2)** 3000 Å (Correct)

- Option 1) 300 Å
**Option 2) 3000 Å**- Option 3) 30 Å
- Option 4) 3 Å

As we all knows that,

The energy (E) of a quantum of radiation –

Where h is plank’s constant and is frequency, and

Speed of electromagnetic radiation –

where frequency is (,pronounced as nu), wavelength is (λ) and velocity of light is(c)

–

We also know,

E= energy of a quantum of radiation

h=plank’s constant

frequency of radiation

and

Now,

Put in 2

So the correct option is 2nd.

**Ans 2) 3000 Å**