Question) If 13.6 eV energy is required to ionize the hydrogen atom, then the energy required to remove an electron from n = 2 is:

If 13.6 eV energy is required to ionize the hydrogen atom, then the energy required to remove an electron from n = 2 is:

Option 1) 10.2 eV

Option 2) 0 eV

Option 3) 3.4 eV

Option 4) 6.8 eV

ANSWER

E=3.4 eV

As we all know that; Ionization energy –

E_{ion }= E_{\infty }-E_{n }
=13.6\frac{Z^{2}}{n^{2}}

Wherein, Energy required to move an electron from ground state to n= \infty

\Delta E =E_{0}z^{2}\left(\frac{1}{n_{i}^{2}}-\frac{1}{n_{f}^{2}} \right )

For an electron to remove from 

n = 2

ni = 2

n_{f}\rightarrow \infty

E_{0}=13.6\ eV     &    z = 1

If 13.6 eV energy is required to ionize the hydrogen atom, then the energy required to remove an electron from n = 2 is

The correct option is 3.4 eV, the 3rd option.

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